Electrochemical equivalent of a divalent metal is $3\times {10}^{-4}gm/coulomb$ . The approximate atomic weight of the metal is

Electro chemical equivalent  is the mass deposited by passing charge of one coloumb

Eq.wt of  the substance  deposits by passing charge of 96500 coloumbs

$96500Coloumbs\left(1F\right)\to E$

$1C\to ?$             

$\therefore$ $e=\frac{E}{F},E=e\times F$ ($\because$ electro chemical equivalent (e)= $\frac{E}{F}$

$e=\frac{E}{F}\Rightarrow E=e\times F$

                       $=3\times {10}^{-4}\times 96500$

                       $=28.95$ g.

$At.wt=E\times valency$                  $\because$     Equivalent weight=$\frac{Atomicweight}{valency}$

            $=28.95\times 2$  

            $=57.9\approx 58g$