Electrode potential data are given below :
$F e^{3 +} (a q) + e^{-} \overset{}{\to} F e^{2 +} (a q); E^{0} = + 0.77 V$
$A l^{3 +} (a q) + 3 e^{-} \overset{}{\to} A l (s); E^{0} = - 1.66 V$
$B r_{2} (a q) + 2 e^{-} \overset{}{\to} 2 B r^{-} (a q); E^{0} = + 1.08 V$
Based on the data, the reducing power of Fe²⁺, Al and Br^- will increase in the order __

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$B r^{-} < F e^{2 +} < A l$

$F e^{2 +} < A l < B r^{-}$

$A l < B r^{-} < F e^{2 +}$

$A l < F e^{2 +} < B r^{-}$

answer is A.

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Detailed Solution

Lesser is the value of reduction potential, more is the reducing character.

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