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Q.

Electrolysis of aqueous ZnSO₄ is carried out using inert electrodes. 4825 amperes of current is passed through the solution for 20 seconds. Weight of substance obtained at cathode is $(Aw of Zn = 65.4)$

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a

65.4 grams

b

1 gram

c

32.7 grams

d

0.5 grams

answer is B.

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Detailed Solution

detailed_solution_thumbnail

Discharge potential of $H^{+} < {Zn}^{2 +}$
$Q = 4825 \times 20 = 96500 C = 1 F$
1F liberates one GEW (1 gram) of
hydrogen at cathode.

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