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Q.

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 moles of H2 gas at the cathode is (1 Faraday = 96500 C mol-1) 

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a

38.6 × 104 sec

b

9.65 × 104 sec

c

28.95 × 104 sec

d

19.3 × 104 sec

answer is B.

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Detailed Solution

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  • When dilute aqueous solution is electrolysed, at cathode, Hydrogen gas and at anode, Oxygen gas are liberated. 
  • 2H2O  +2 e- →H2.
  • For liberation of 1 mole of H2, 2 moles of e- are required .
  • 0.01 moles of H2 will require 2 X 0.01 = 0.02 moles of electrons or 0.02 faradays.
  • Charge required = i X t
  • Time ( t  ) = Charge Current
  • i= 10 mill ampere = 10 X 10-3 ampere.
  • t= 0.02  X 9650010 X 10-3=19.3  X 104 seconds.
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