Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8

Q.

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 moles of H2 gas at the cathode is (1 Faraday = 96500 C mol-1

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

38.6 × 104 sec

b

9.65 × 104 sec

c

28.95 × 104 sec

d

19.3 × 104 sec

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail
  • When dilute aqueous solution is electrolysed, at cathode, Hydrogen gas and at anode, Oxygen gas are liberated. 
  • 2H2O+2 e- H2.
  • For liberation of 1 mole of H2, 2 moles of e- are required .
  • 0.01 moles of H2 will require 2 X 0.01 = 0.02 moles of electrons or 0.02 faradays.
  • Charge required = i X t
  • Time (t ) = Charge Current
  • i= 10 mill ampere = 10 X 10-3 ampere.
  • t= 0.02 X 9650010X 10-3=19.3 X 104 seconds.
Watch 3-min video & get full concept clarity

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon