Electromagnetic radiation having $λ = 310 A^{0}$ is subjected to a metal sheet having work function = 12.8 eV. What will be the velocity of photo-electrons having maximum kinetic energy.

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$3.09 \times 10^{6} m / s$

$8.2 \times 10^{6} m / s$

0, no emission will occur

$4.352 \times 10^{6} m / s$

answer is C.

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Detailed Solution

$\frac{1}{2} m v^{2} = \frac{1240 e v}{31 n m} n m = 12.8 e v = 27. e v \Rightarrow \frac{1}{2} \times 9.1 \times 10^{- 31} \times v^{2} = 27.2 \times 1.6 \times 10^{- 19}$

$v = 3.09 \times 10^{6} m / s$

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