Element ‘B’ forms CCP structure and ‘A’ occupies half of the octahedral voids. While oxygen atoms occupy all the tetrahedral voids. The formula of bimetallic oxide is

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${AB}_{2} O_{4}$

$A_{4} B_{2} O$

$A_{2} B_{2} O$

$A_{2} {BO}_{4}$

answer is A.

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Detailed Solution

$B \Rightarrow CCP \Rightarrow B_{4}$ Total B atoms =4

N = 4 oh voids = 4 Td voids = 8

$A \Rightarrow \frac{1}{2} o h \Rightarrow \frac{4}{2} = 2$

$O \Rightarrow T d \Rightarrow 8$

$B_{4} A_{2} O_{8} \Rightarrow {A B}_{2} O_{4}$

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