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Q.

Element ‘B’ forms CCP structure and ‘A’ occupies half of the octahedral voids. While oxygen atoms occupy all the tetrahedral voids. The formula of bimetallic oxide is                  

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a

A2B2O

b

AB2O4

c

A2BO4

d

A4B2O

answer is A.

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Detailed Solution

B ⇒  CCP  ⇒  B4 Total B atoms =4

N = 4       oh voids = 4 Td voids = 8

A ⇒ 12 oh ⇒ 42 = 2

O  ⇒  Td   ⇒  8

B4  A2 O8   ⇒   A B2O4

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