Elements A,B, C,D and E have following electronic configurations :
(A) $1 s^{2}, 2 s^{2} 2 p^{1}$ (B) $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{1}$
(C) $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{3}$ (D) $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{5}$
(E) $1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6}$
Which among the belongs to same group in the periodic table?

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A and E

A and D

A and B

A and C

answer is D.

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Detailed Solution

The electronic configuration of Boron is,

$1 s^{2}, 2 s^{2} 2 p^{1}$
The electronic configuration of Aluminum is,

$1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{1}$

Both belongs to same group in the periodic table.

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