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Q.

Elevation in b.p. of an aqueous solution urea solution is 0.52∘.Kb=0.52∘mol−1kg Hence, mole fraction of urea in this solution is : 

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a

0.567

b

0.982

c

0.943

d

0.018

answer is D.

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Detailed Solution

As,

m= moles of solute Kg of solvent =1

Thus,

m=0.520.52=1=n1(kg)⇒Xurea =11+100018=0.018

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