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Q.

Elimination reaction of 2- bromopentane to form pent-2-ene is
(A) $β$ -Elimination reaction
(B) follows Zaitsev rule
(C) dehydrohalogenation reaction
(D) dehydration reaction.

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a

(A), (C), (D)

b

(A), (B), (D)

c

(A), (B), (C)

d

(B), (C), (D)

answer is A.

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Detailed Solution

$\overset{5}{C H_{3}} - \overset{4}{C H_{2}} - \overset{3}{C H_{2}} - \overset{\overset{B r}{2 |}}{C H} - \overset{I}{C H_{3}} \to_{(- H B r)}^{β - E l i m i n a t i o n}$
2-Bromopentane
dehydrobromination
$\overset{5}{C H_{3}} - \overset{4}{C H_{2}} - \overset{3}{C H} = \overset{2}{C H} - \overset{1}{C H_{3}}$
Pent-2-ene
(more substituted alkene is formed, zaitsev’s rule)

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Elimination reaction of 2- bromopentane to form pent-2-ene is(A) β -Elimination reaction(B) follows Zaitsev rule(C) dehydrohalogenation reaction(D) dehydration reaction.