EMF of the cell  $\mathrm{Zn}\left(\mathrm{s}\right)/{\mathrm{Zn}}^{+2}\left(0.01\mathrm{M}\right)//{\mathrm{Ag}}^{+}$(0.1M)/Ag(s) is equal to $\left(E_{Z{n}^{+2}/Zn}^0=-0.76V;E_{A{g}^{+}/Ag}^0=+0.8V\right)$

$E_{Cell}^0=E_{Ag}^0-E_{Zn}^0=0.8-\left(-0.76\right)=+1.56v$

$\underset{\left(S\right)}{\overset{ }{Zn}}+2\underset{\left(0.1M\right)}{\overset{+}{Ag}}\rightleftharpoons \underset{\left(0.01M\right)}{\overset{2+}{Zn}}+\underset{\left(s\right)}{\overset{ }{2Ag}}$

$E_{Cell}=E_{Cell}^0-\frac{0.06}{n}\log \frac{\left[\stackrel{2+}{Zn}\right]}{{\left[\stackrel{+}{Ag}\right]}^2}=1.56-\frac{0.061}{2}\log \frac{\left({10}^{-2}\right)}{{\left({10}^{-1}\right)}^2}$= 1.56v