$E, m, l$and G denote energy, mass, angular momentum and gravitational constant respectively, then the dimension of $\frac{E{l}^2}{m^5{G}^2}$ are

$\left[E\right]=\text{ energy }=\left[M{L}^2{T}^{-2}\right]$

$\begin{array}{l}\left[m\right]=\text{ mass }=\left[M\right]\\ \left[l\right]=\text{ Angular momentum }=\left[M{L}^2{T}^{-1}\right]\\ \left[G\right]=\text{ Gravitational constant }=\left[M^{-1}{L}^3{T}^{-2}\right]\end{array}$

Substituting dimensions of above quantities in $\frac{E{l}^2}{m^5{G}^2}$

$=\frac{\left[M{L}^2{T}^{-2}\right]\times {\left[M{L}^2{T}^{-1}\right]}^2}{\left[M^5\right]\times {\left[M^{-1}{L}^3{T}^{-2}\right]}^2}=\left[M^0{L}^0{T}^0\right]$

i.e., the quantity should be angle.