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$E_{M n^{2 +} / M n O_{4}^{-}}^{0} = - 1.52 V$ and $E_{P t, O_{2} / H_{2} O}^{0} = + 1.23 V$ Can permanganate oxidise water ?

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Yes, $E_{c e l l}^{0} = + 0.29 V$

No, $E_{c e l l}^{0} = - 0.29 V$

No, $E_{c e l l}^{0} = - 2.75 V$

Yes, $E_{c e l l}^{0} = + 2.75 V$

answer is A.

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Detailed Solution

$\begin{array}{l} E_{M n O_{4}^{-} / M n^{2 +}}^{0} = + 1.52 V \\ E_{P t, O_{2} / H_{2} O}^{0} = + 1.23 V \end{array}$

For the reaction

$M n O_{4}^{-} + H_{2} O \overset{H^{+}}{\to} M n^{2 +} + O_{2}, E_{c e l l}^{0} = (1.52 - 1.23) V$

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