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Q.

EN of the element (A) is  E1 and IP is E2 . Hence EA will be

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a

2E1-E2

b

E1-E2

c

E1-2E2

d

E1+   E2/2

answer is A.

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Detailed Solution

 E.N = I.E+E.A 2 (fromMullkenScale
E1=E2+EA22E1=E2+EAEA=2E1-E2

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