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Q.

End B of a thin rod of length ‘l’ is hinged so that it can swing in a vertical plane. ‘S’ is a stopper at a distance ‘x’ below the hinge B. Initially the rod is held in horizontal position by an external agent as shown in figure. After the rod is released it swings in a vertical plane and when it becomes vertical it strikes the stopper S and stops. If during the course of impact the horizontal component of reaction at the hinge B is zero, find x.

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a

l2

b

2l3

c

3l4

d

5l6

answer is B.

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Detailed Solution

During the course of impact moment of all external forces about point S is zero and hence angular momentum of the rod about S is conserved.

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Just after the impact angular momentum of the rod about S, Lf = 0.

Linear momentum of the element of length dr is given by, 

dP=dm×V=ml  dr   ωr=l   rdr

Therefore angular momentum of the rod about S before impact is given by

Li=  0x  xr  dP           xl  rx  dP

=  x  0x  l  rdr     0x  l  r2dr   xl  l  r2dr     +   x   xl  l  rdr  

=  l    x32    x33    l33  +   x33  +  xl22     x32

=  l    xl22    l33

Now   Li=Lf     l   xl22    l33=  0     x  =  2l3

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