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Q.

Energy of a quanta of frequency $10^{15} Hz and h = 6 .6 \times 10^{- 34} J - \sec$ will be

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a

$6 .6 \times 10^{- 49} J$

b

$6 .6 \times 10^{- 41} J$

c

$6 .6 \times 10^{- 12} J$

d

$6 .6 \times 10^{- 19} J$

answer is A.

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Detailed Solution

$E = hv = 6 .6 \times 10^{- 34} \times 10^{15} = 6 .6 \times 10^{- 19} J$

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