Energy of the electron in nth orbit of hydrogen atom is given by $E_{n} = - \frac{13.6}{n^{2}} eV$ . The amount of energy needed to transfer electron from first orbit to third orbit is

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1.51 eV

3.4 eV

12.09 eV

13.6 eV

answer is C.

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Detailed Solution

For $n = 1, E_{1} = - \frac{13.6}{{(1)}^{2}} = - 13.6 eV$
and for n = 3, $E_{3} = - \frac{13.6}{{(3)}^{2}} = - 1.51 eV$
So required energy
$= E_{3} - E_{1} = - 1.51 - (- 13.6) = 12.09 eV$

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