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Q.

Energy released in Radioactive decay process XY+y is equal to

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a

sum of rest energy of Y and y minus rest energy of X

b

binding energy of X minus sum of binding energy of Y and y

c

rest energy of X minus sum of rest energy of Y and y

d

sum of binding energy of Y and y minus binding of X

answer is B, C.

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Detailed Solution

By law of conservation of energy we get

mxc2+Kx=mYc2+KY+myc2+Ky Q=mxc2-mYc2-mYc2=Ky+Ky-KX

Since, X is at rest so the energy released Q is 

Q=mxc2-myc2-myc2=Ky+Ky

The Q value i.e. energy released is the rest energy of X minus rest energy of Y and y

When binding energy of products is more than binding energy of parent nucleus, then energy is released.

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