Energy released in the fission of a single $_{92} U^{235}$ nucleus is 200 MeV. The fission rate of a $_{92} U^{235}$ fuelled reactor operating at a power level of 5W is

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$1 .56 \times 10^{+ 10} s^{- 1}$

$1 .56 \times 10^{+ 11} s^{- 1}$

$1 .56 \times 10^{+ 16} s^{- 1}$

$1 .56 \times 10^{+ 17} s^{- 1}$

answer is B.

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Detailed Solution

$\frac{Energy}{Fission} = 200 MeV = 200 \times 10^{6} \times 1 .6 \times 10^{- 19} J$
$Fission rate = \frac{5}{200 MeV} = 1 .56 \times 10^{11} fission/sec.$

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