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Q.

Enthalpies of formation of CCl4(g),H2O(g),CO2(g)  and  HCl(g)are -105, -242, -394 and 
-92 KJ   mol1  respectively. The magnitude of enthalpy of the reaction given below is__KJ/mol (nearest integer)
 CCl4(g)+2H2O(g) CO2(g)+4HCl(g)
 

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answer is 173.

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Detailed Solution

ΔH=HPHR =[394+(4×92)][105+(2×242)] =173  KJ/mol

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