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Q.

Enthalpy of atomization of sodium metal is $108 KJ / mole$ . Ionisation potential of sodium will be $({Na}_{(s)} \to_{}^{} {Na}_{(g)}^{+}, Δ H = + 600 KJ)$

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a

$708 KJ / mole$

b

$- 708 KJ / mole$

c

$492 KJ / mole$

d

$- 492 KJ / mole$

answer is A.

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Detailed Solution

$Na (s) \to_{}^{} Na (g); Δ H = + 108 KJ$
$Na (s) \to_{}^{} {Na}^{+} (g); Δ H = + 600 KJ$
(2) – (1)
$Na (g) \to_{}^{} {Na}^{+} (g); Δ H = + 492 KJ$

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Enthalpy of atomization of sodium metal is 108 KJ/mole . Ionisation potential of sodium will be Nas→ Nag+,ΔH=+600 KJ