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Q.

Enthalpy of combustion of  diamond is 94.5 kcal/mole and Enthalpy of combustion of graphite is 94 kcal/mole. Enthalpy change when one mole of diamond converts to one mole of graphite is

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a

+500 cal

b

-188.5 kcal

c

-500 cal

d

+188.5 kcal

answer is C.

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Detailed Solution

Combustion is always exothermic, H=-ve; Cdiamond+O2g CO2g; H=-94.5 kcal -I ; Cgraphite+ O2g CO2g; H=-94 kcal -II; Eq I - Eq II Cdiamond Cgraphite; H=-0.5 kcal/mole 

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Enthalpy of combustion of  diamond is 94.5 kcal/mole and Enthalpy of combustion of graphite is 94 kcal/mole. Enthalpy change when one mole of diamond converts to one mole of graphite is