Enthalpy of combustion of Rhombic sulphur is -2400 kJ/mole. Enthalpy os formation sulphur dioxide is

Rhombic sulphur is S₈(α)

$\begin{array}{l}{\mathrm{S}}_8\left(\mathrm{\alpha }\right)+8{\mathrm{O}}_2\left(\mathrm{g}\right)\to 8{\mathrm{SO}}_2\left(\mathrm{g}\right),\mathrm{\Delta H}=-2400\mathrm{kJ} ;\\ \mathrm{Dividing} \mathrm{throughout} \mathrm{by} 8\\ \frac{1}{8}{\mathrm{S}}_8\left(\mathrm{\alpha }\right)+{\mathrm{O}}_2\left(\mathrm{g}\right)\to {\mathrm{SO}}_2\left(\mathrm{g}\right),\mathrm{\Delta H}= -300\mathrm{kJ} ;\\ \mathrm{Standard} \mathrm{enthalpy} \mathrm{of} \mathrm{formation} \mathrm{of} {\mathrm{SO}}_2 \mathrm{is} -300 \mathrm{kJ}/\mathrm{mole} ;\end{array}$