Enthalpy of neutralization of all strong acids and strong bases has the same value because

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Neutralisation leads to the formation of a salt and water

Strong acid and bases are ionic substances

Acids always furnish $H^{+}$ ions and bases always furnish ${OH}^{-}$ ions

The net chemical change involves the combination of $1 m o l$ of $H^{+}$ ions and $1 m o l$ ${OH}^{-}$ ions to form water

answer is A.

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Detailed Solution

$HCl + NaOH \to NaCl + H_{2} O Δ H_{neutralization} = - 13.7 Kcal$

Because when strong acid reacts with a strong base, then there is a formation of salt and water and hence, enthalpy of neutralization is the same.

Hence the correct answer is (A) Neutralization leads to the formation of a salt and water.

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