Enthalpy of sublimation of Iodine is 63 kJ/mole. Enthalpy of atomisation of Iodine (g) is 157 kJ/mole. Change in enthalpy for the process, $2 I (g) \to I_{2} (s)$ will be

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-220 kJ/mole

-110 kJ/mole

+110 kJ/mole

+220 kJ/mole

answer is A.

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Detailed Solution

$I_{2} (s) \to I_{2} (g), ∆ H = + 63 kJ . . . . . (1); I_{2} (g) \to 2 I (g), ∆ H = + 157 kJ . . . . . (2); Adding (1) and (2) I_{2} (s) \to 2 I (g), ∆ H = + 220 kJ; 2 I (g) \to I_{2} (s), ∆ H = - 220 kJ;$

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