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Enzymes convert glucose (M = 180.2) to ethanol (M = 46.1) according to the equation
$C_{6} H_{12} O_{6} ⟶ 2 C_{2} H_{5} OH + 2 {CO}_{2}$
What is the maximum mass of ethanol that can b made from 16.5 kg of glucose?

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7.93 kg

0.512 kg

3.96 kg

0.256 kg

answer is D.

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Detailed Solution

Moles of glucose $= \frac{15 \cdot 5 \times 10^{3}}{180 \cdot 2}$

Moles of ethanol terms $= \frac{15 : 5}{180.2} \times 2$

Mass of ehanol terms $\begin{aligned} = \frac{15.5 \times 2 \times 06}{180.2} \\ = 7.93 kg \end{aligned}$

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