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Q.

E^o of Fe|Fe²⁺ is +0.44V, E^o of Cu|Cu²⁺ is –0.32V. Then in the cell

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a

Cu oxidises Fe²⁺ ion

b

Cu²⁺ oxidises iron

c

Cu reduces Fe²⁺ ion

d

Cu²⁺ ion reduces Fe

answer is B.

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Detailed Solution

Both potentials are oxidation potentials. Higher oxidation potental reduces lower oxidation potential

Fe reduces Cu⁺² or Cu⁺² oxidises Fe.

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Eo of Fe|Fe2+ is +0.44V, Eo of Cu|Cu2+ is –0.32V. Then in the cell