Eo Values of some elements are given below I2+2e−→ 2I−;Eo=+0.54V MnO4−+8H++5e−→ Mn2++4H2O;Eo=+1.52V Fe3++e−→ Fe2+;Eo=+0.77V Sn4++2e−→ Sn2+;Eo=+0.1VThen, identify the correct statement(s) among the following

A) Eo(Sn4+|Sn2+) is lowest B) SRP values indicate that MnO4− ion has highest tendency to undergo reductionC) Sn4++2I−→ Sn2++I2 Ecello=RP(sn4+|Sn2+)+OP(I−|I2) =0.1−0.54=−0.44V ∴ Non-spontaneousD) Sn2++I2→ Sn4++2I− Ecello=Eco−EAo=0.54−0.1=0.44VEcello=+Ve⇒ spontaneous.

Eo Values of some elements are given below I2+2e−→ 2I−;Eo=+0.54V MnO4−+8H++5e−→ Mn2++4H2O;Eo=+1.52V Fe3++e−→ Fe2+;Eo=+0.77V Sn4++2e−→ Sn2+;Eo=+0.1VThen, identify the correct statement(s) among the following

A) Eo(Sn4+|Sn2+) is lowest B) SRP values indicate that MnO4− ion has highest tendency to undergo reductionC) Sn4++2I−→ Sn2++I2 Ecello=RP(sn4+|Sn2+)+OP(I−|I2) =0.1−0.54=−0.44V ∴ Non-spontaneousD) Sn2++I2→ Sn4++2I− Ecello=Eco−EAo=0.54−0.1=0.44VEcello=+Ve⇒ spontaneous.

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$E^{o}$ Values of some elements are given below
$I_{2} + 2 e^{-} \to_{}^{} 2 I^{-}; E^{o} = + 0.54 V$
$M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to_{}^{} M n^{2 +} + 4 H_{2} O; E^{o} = + 1.52 V$
$F e^{3 +} + e^{-} \to_{}^{} F e^{2 +}; E^{o} = + 0.77 V$
$S n^{4 +} + 2 e^{-} \to_{}^{} S n^{2 +}; E^{o} = + 0.1 V$
Then, identify the correct statement(s) among the following

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$M n O_{4}^{-}$ is stronger oxidizing agent than $I_{2}$ and $F e^{3 +}$

$S n (I V)$ can oxidize $I^{-} i o n t o I_{2}$

$S n (I I)$ can reduce $I_{2}$ to $I^{-}$ ion

Correct order of reducing ability: $S n^{2 +} > F e^{2 +} > M n^{2 +}$

answer is A, B, D.

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Detailed Solution

A) $E^{o} (S n^{4 +} | S n^{2 +})$ is lowest
B) SRP values indicate that $M n O_{4}^{-}$ ion has highest tendency to undergo reduction
C) $S n^{4 +} + 2 I^{-} \to_{}^{} S n^{2 +} + I_{2}$
$E_{c e l l}^{o} = R P (s n^{4 +} | S n^{2 +}) + O P (I^{-} | I_{2})$
$= 0.1 - 0.54 = - 0.44 V$
$∴$ Non-spontaneous
D) $S n^{2 +} + I_{2} \to_{}^{} S n^{4 +} + 2 I^{-}$
$E_{c e l l}^{o} = E_{c}^{o} - E_{A}^{o} = 0.54 - 0.1 = 0.44 V$
$E_{c e l l}^{o} = + V e \Rightarrow$ spontaneous.