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Equal currents of 2A flows in the two segments of a circular loop as shown in figure. Radius of circular loop is 10cm. Magnetic field at the centre of the loop ‘O’ is $n π \times 10^{- 6} T$ Where ‘n’ is

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answer is 2.

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Detailed Solution

$B = \frac{μ_{0} I}{2 r} (\frac{270}{360}) - \frac{μ_{0} I}{2 r} (\frac{90}{360}) \Rightarrow B = 2 π \times 10^{- 6} T \Rightarrow n = 2$

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