Equal mass of a solute is dissolved in equal mass of two solvents A and B and forms a very dilute solution. The relative lowering of vapour pressure for the solution B has twice the relative lowering vapour pressure for the solution A. if M_A and M_B are the molecular mass of solvents A and B are respectively then

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M_A = M_B

M_A = 2M_B

M_A =4 M_B

M_B = 2M_A

answer is B.

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Detailed Solution

$\frac{p^{0} - p}{p^{0}} = \frac{n}{n + N} = \frac{n}{N}$ (For very dilute solution)
Given $2 \frac{n}{N_{A}} = \frac{n}{N_{B}}$
$\begin{array}{l} 2 X \frac{1}{(\frac{W_{A}}{M_{A}})} = \frac{1}{(\frac{W_{B}}{M_{B}})} \\ 2 X \frac{M_{A}}{W_{A}} = \frac{M_{B}}{W_{B}} \\ ∴ M_{B} = 2 M_{A} (W_{A} = W_{B}) \end{array}$

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