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Equal moles of CO, $B_{2} H_{6}, H_{2} and {CH}_{4}$ are placed in a container. If a hole was made in container after 5 minute, partial pressure of gases in container would be
(Atomic weights of C, O, B and H are 12, 16, 11, 1 respectively)

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$P_{CO} > P_{B_{2} H_{6}} > P_{H_{2}} > P_{{CH}_{4}}$

$P_{CO} = P_{B_{2} H_{6}} > P_{{CH}_{4}} > P_{H_{2}}$

$P_{CO} > P_{B_{2} H_{6}} = P_{H_{2}} > P_{{CH}_{4}}$

$P_{B_{2} H_{6}} > P_{H_{2}} > P_{{CH}_{4}} > P_{CO}$

answer is B.

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Detailed Solution

$CO and B_{2} H_{6}$ have same molecular mass. The diffusion of lighter gas will be more. Thus moles coming out from container will show.

$H_{2} > {CH}_{4} > CO = B_{2} H_{6} .$

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