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Equal volumes of 1 x 10^-4 M solutions of Cd²⁺ and ${CO}_{3}^{2 -}$ ions are mixed in one flask and equal volumes of lx 10^-4 M solutions of Ag⁺ and ${CrO}_{4}^{2 -}$ ions are mixed in a second. Which substances precipitate?
Formula ${CdCO}_{3}$ ${Ag}_{2} {CrO}_{4}$
$K_{s p}$ 5.2 X 10^-12 1.1 X 10^-12

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${CdCO}_{3}$ only

${Ag}_{2} {CrO}_{4}$ only

Both

Neither

answer is A.

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Detailed Solution

$\begin{array}{l} K_{i p} ({CdCO}_{3}) = \frac{10^{- 4}}{2} \times \frac{10^{- 4}}{2} > k_{s p} \end{array}$

$K_{i p} ({Ag}_{2} {CrO}_{4}) = {(\frac{10^{- 4}}{2})}^{2} \times \frac{10^{- 4}}{2} < k_{s p}$

Hence, ${CdCO}_{3}$ will precipitate.

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