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Equal weight of ' X ' (At. wt. =36 ) and ' Y ' (At. wt. = 24) are reacted to form the compound $X_{2} Y_{3}$ . Then:

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X is the limiting reagents

Y is the limiting reagents

no reactant is left over

mass of $X_{2} Y_{3}$ formed is double the mass of $' X'$ taken

answer is C, D.

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Detailed Solution

To form one molecule of $X_{2} Y_{3}$ , two atoms of X and three atoms of Y will be needed.

$\begin{array}{l} 2 X + 3 Y ⟶ X_{2} Y_{3} \\ \frac{W}{36} \frac{W}{24} \\ - - \frac{W}{72} \times [72 \times 2] \end{array}$

It means $36 \times 2 = 72 amu$ of X and $24 \times 3 = 72 amu$ of Y will be needed to form, $144 amu$ of $X_{2} Y_{3}$ .

Hence, the correct option is c and d.

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