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Q.

Equal weight of NaCl and KCI are dissolved separately in equal volumes of solutions. Molarity of the two solutions will be :

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a

that of NaCl will be more than that of KCI solution

b

that of NaCl will be half than that of KCl solution

c

equal

d

that of NaCl will be less than that of KCI solution

answer is C.

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Detailed Solution

Mkcl=39+35.5=74.5

Equal weight 74.58

nNcl=74.558.5=127

mnacl =74.574.5=1 mole 

 Molarity = number of moles V

=n1 lite

nNaCl>nKCl :MNaCl>MKCl

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Equal weight of NaCl and KCI are dissolved separately in equal volumes of solutions. Molarity of the two solutions will be :