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Q.

Equation of sphere whose centre is at 7i4j + k and radius 3i-2 j + 5k , is

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a

r 2 -2r.(3i - 2j + 5k ) + 28 = 0

b

r 2 -2r.(3i - 2j + 5k ) - 28 = 0

c

r 2 -2r.(7i - 4j + k ) - 28 = 0

d

r 2 -2r.(7i - 4j + k ) + 28 = 0

answer is B.

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Detailed Solution

r-(7i-4j+k)=9+4+25 r-(7i-4j+k)2=38 r2-2r.(7i-4j+k)+28=0

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