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Equation of the acute angular bisector of the planes 2x – y – 2z – 6 = 0, 3x + 2y –6z–12 = 0 is

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5x–13y+4z–6=0

23x–y–32z–6=0

23x–y–32z–78=0

5x–13y+4z–78=0

answer is C.

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Detailed Solution

$a_{1} a_{2} + b_{1} b_{2} + c_{1} c_{2} = 6 - 2 + 12 > 0$

$∴$ Equation of acute angle to bisector is

$\frac{2 x - y - 2 z - 6}{3} = \frac{3 x + 2 y - 6 z + 2}{7}$

14x -7y-14z-42 = -9x-6y+18z + 36

23x –y – 32z – 78 = 0

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