Equation of the circle, which is the mirror image of the circle $x^2+y^2-2x=0$ with respect to the line $x+y=2$ is

Given   $x^2+y^2-2x=0$

Centre $\left(\mathrm{c}\right)=(1,0)$ , radius =1

Centre of the require circle be  $p(h,k)$

P is image of c w.r.t. the line  $x+y-2=0$

$\therefore \frac{\mathrm{h}-1}{1}=\frac{\mathrm{k}-0}{1}=\frac{-2(1+0-2)}{1^2+1^2}\Rightarrow (\mathrm{h},\mathrm{k})=(2,1)$

$\therefore$ require circle is   $(x-2{)}^2+(y-1{)}^2=1^2$