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Equations of motion of a projectile are given by $x = 36 t and 2 y = 96 t - 98 t^{2} m .$ The angle of projection is equal to

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$\sin^{- 1} (\frac{3}{4})$

$\sin^{- 1} (\frac{4}{3})$

$\sin^{- 1} (\frac{4}{5})$

$\sin^{- 1} (\frac{3}{5})$

answer is C.

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Detailed Solution

$u \cos θ = 36$ …..(1)
$u \sin θ = 48$ …..(2)
Solving (1) & (2) equations

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