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Equations of motion of a projectile are given by $x = 36 t$ and 2y = 96t -98t²m. The angle of projection is equal to (2011 - M)

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$\sin^{- 1} (\frac{3}{4})$

$\sin^{- 1} (\frac{4}{3})$

$\sin^{- 1} (\frac{4}{5})$

$\sin^{- 1} (\frac{3}{5})$

answer is C.

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Detailed Solution

u cos $θ$ = 36 - - - (1) ; u sin $θ$ = 48 - - - (2)

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