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Q.

Equilibrium constant for the formation of $H I (g)$ as:
$H_{2} (g) + I_{2} (g) \underset{}{⇌} 2 HI (g)$ can be expressed as $\log k = \frac{270}{T} + 0.4. Then Δ G =_____k J at 500K$

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a

$- 9.96$

b

$- 7.96$

c

$- 8.96$

d

$- 10.96$

answer is B.

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Detailed Solution

$l o g K = - Δ H / 2.303 R T + Δ S / 2.303 R$

$Δ S = 0.4 x 2.303 x R = 7.645 J K^{- 1}$

$Δ H = - (270 x 2.303 x R) = - 5161 J$

$Δ G = Δ H - T Δ S = - 8961 J$

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