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Q.

Equilibrium constant for the reaction $H_{2} O_{(g)} + C O_{(g)} ⇌ H_{2 (g)} + C O_{2 (g)}$ is 81. If the velocity constant of the forward reaction is $162 l i t m o l^{- 1} \sec^{- 1}$ , What is the velocity constant (in lit $m o l^{- 1} \sec^{- 1}$ ) for the backword reaction?

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a

2

b

243

c

261

d

13.22

answer is B.

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Detailed Solution

$\begin{array}{l} K_{C} = \frac{K_{f}}{K_{b}} \\ 81 = \frac{162}{K_{b}} \Rightarrow K_{b} = \frac{162}{81} = 2 \end{array}$

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Equilibrium constant for the reaction H2O(g)+CO(g)⇌H2(g)+CO2(g) is 81. If the velocity constant of the forward reaction is 162 lit mol−1sec−1, What is the velocity constant (in lit mol−1sec−1 ) for the backword reaction?