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Q.

Equilibrium constants for four different reactions are given as $k_{1} = 10^{6}, k_{2} = 10^{- 4}, k_{3} = 10$ and $k_{4} = 1 .$ Which reaction will take maximum time to attain equilibrium?

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a

$k_{4} = 20$

b

$k_{1} = 10^{2}$

c

$k_{3} = 10$

d

$k_{2} = 10^{- 4}$

answer is B.

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Detailed Solution

Minimum the value of equilibrium constant, maximum time it will take to achieve equilibrium.

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