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Equilibrium for which K_P = K_C is

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${CaCO}_{3} (s) ⇌ CaO (s) + {CO}_{2} (g)$

${PCl}_{5} (g) ⇌ {PCl}_{3} (s) + {Cl}_{2} (g)$

$2 {SO}_{3} (g) ⇌ 2 {SO}_{2} (g) + O_{2} (g)$

$H_{2} (g) + I_{2} (g) ⇌ 2 Hl (g)$

answer is D.

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Detailed Solution

$K_{P} = K_{C} (RT)^{{Δn}_{g}} For H_{2} (g) + l_{2} (g) ⇌ 2 Hl (g) since {Δn}_{g} = 0 therefore K_{P} = K_{C}$

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