Equimolar solutions of KCl and compound X in water show depression in freezing point in the ratio of 4:1. Assuming KCl to be completely ionized, the compound X in the solutions must:

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Equimolar solutions of $K C l$ and compound X in water show depression in freezing point in the ratio of 4:1. Assuming $K C l$ to be completely ionized, the compound X in the solutions must:

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Dissociate to the extent of 50%

Dissociate to the extent of 80%

Trimerise to the extent of 75%

Dimerise to the extent of 50%

answer is D.

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Detailed Solution

$m_{K C l} = m_{x}$

$∴ \frac{Δ T_{f (K C l)}}{i_{K C l}} = \frac{Δ T_{f (X)}}{i_{(x)}}, i_{(X)} = \frac{1}{2}$

For trimerisation of 75% extent $i = 1 + (\frac{1}{6} - 1) \times \frac{3}{4}, i = \frac{1}{2}$

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