Equipotential surfaces representing a uniform electric field must be

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$s p a c e d s u c h t h a t s u r f a c e s h a v i n g e q u a l d i f f e r e n c e i n p o t e n t i a l a r e s e p a r a t e d b y e q u a l d i s \tan c e$

$p l a n e s u r f a c e s .$

$h a v i n g p o t e n t i a l s d e c r e a \sin g i n t h e d i r e c t i o n o f t h e f i e l d .$

$n o r m a l t o t h e d i r e c t i o n o f t h e f i e l d$

answer is A, B, C, D.

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Detailed Solution

For Uniform electric field

Electric lines of force are always perpendicular to equipotential surfaces. For uniform electric field equi-potential surfaces are plane surfaces.

E = $\frac{△ V}{△ r} .$ For constant E and constant $△ V, △ r e m a i n s c o n s \tan t .$

Electric field is always directed from point of higher potential to lower potential .

Hence correct answer is 1,2,3,4

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