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Q.

Equivalent conductance of saturated ${BaSO}_{4}$ is $400 {ohm}^{- 1} {cm}^{2} {eq}^{- 1}$ and specific conductance is $8 \times 10^{- 5} {ohm}^{- 1} {cm}^{- 1}$ . Hence solubility product of ${BaSO}_{4}$ is

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a

$10^{- 6} M^{2}$

b

$4 \times 10^{- 4} M^{2}$

c

$2 \times 10^{- 5} M^{2}$

d

$10^{- 8} M^{2}$

answer is D.

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Detailed Solution

$Λ_{eq} = \frac{k \times 1000}{N}$

$N = \frac{8 \times 10^{- 5} \times 10^{3}}{400}$

$= 2 \times 10^{- 4}$

$S = M = 10^{- 4}$

$K_{sp} = S^{2} = 10^{- 8}$

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Equivalent conductance of saturated BaSO4 is 400 ohm−1cm2eq−1 and specific conductance is 8×10−5ohm−1cm−1. Hence solubility product of BaSO4 is