Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Equivalent conductivity of AgNO3 ,  CaCl2 andCaNO32  at infinite dilution are 110, 230 and 196.5Ω1cm2eqv1 respectively. Conductivity of saturated solution of AgCl(aq.) & H2O , used to prepare solution, is 2.4×106Ω1cm1 and  1.4×106Ω1cm1 respectively. Find amount of AgCl(mg/L) in its saturated solution  mg/litre. Report the value to nearest integer.
[Atomic mass: Ag = 108, Cl = 35.5]
 

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

(110+230196.5)=(2.4×1061.4×106)×103C(mollitre) 
C=103143.5mollitre 
S=103143.5×143.5gm=1mglitre=1.00 

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon