Equivalent conductivity of Al2(SO4)3 is related to its molar conductivity by the expression of

Λeq=k×1000N (N=n×M)Λeq=k×1000n×MForAl2SO43n=6Λeq=Λm6

Equivalent conductivity of Al2(SO4)3 is related to its molar conductivity by the expression of

Λeq=k×1000N (N=n×M)Λeq=k×1000n×MForAl2SO43n=6Λeq=Λm6

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Equivalent conductivity of Al₂(SO₄)₃ is related to its molar conductivity by the expression of

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Λeq=Λm3

Λeq=6Λm

Λeq=Λm6

Λeq=Λm

answer is C.

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$\begin{array}{l} Λ_{eq} = \frac{k \times 1000}{N} (N = n \times M) \\ Λ_{eq} = \frac{k \times 1000}{n \times M} \\ For {Al}_{2} {({SO}_{4})}_{3} \\ n = 6 \\ Λ_{eq} = \frac{Λ_{m}}{6} \end{array}$

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Equivalent conductivity of Al2(SO4)3 is related to its molar conductivity by the expression of

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Equivalent conductivity of Al₂(SO₄)₃ is related to its molar conductivity by the expression of