Equivalent mass of FeC2O4 in the change, FeC2O4→Fe+3+CO2 is M/x, x is

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Equivalent mass of $F e C_{2} O_{4}$ in the change, $F e C_{2} O_{4} \to F e^{+ 3} + C O_{2} i s M / x, x i s$

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answer is 3.

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$F e^{+ 2} \to F e^{+ 3} + e^{-}$

$C_{2} O_{4}^{- 2} \to 2 C O_{2} + 2 e^{-}$

Adding both the reactions , we get

$F e^{+ 2} + C_{2} O_{4}^{- 2} \to 2 C O_{2} + F e^{+ 3} + 3 e^{-}$

Equivalent weight is defined as the molecular weight divided by the number of moles of electron required by the molecule.

Hence equivalent weight is equal to $\frac{M}{3} = \frac{M}{x}$

Therefore $x = 3$ .

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