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Q.

Equivalent Weight of dil.HNO3 when it reacts with Zn is (At.wt of Zn = 65)

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a

65

b

c

d

answer is D.

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Detailed Solution

4Zn+10 HNO3(dil.)→4Zn(NO3)2+5H2O+N2O

HNO3 in this reaction acts like both acid and Oxidant

E.W of HNO3 as an acid. It forms Zn(NO3)2

No.of replaceable H-atoms in HNO3 = 1

E.W of HNO3 (acid) = M/1 =M

E.W of HNO3 as an Oxidant

                                

mathop Nlimits^{ + 5} O_3^ - to mathop {{N_2}}limits^{ + 1} O

decrease in Ox. state =4

E.W of HNO3 (oxidant) = M/4

therefore Over all ;EW; of; HNO3 =frac{M}{1}+frac{M}{4}=frac{5M}{4}

                                                      

=frac{5(65)}{4}
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