Error in the measurement of radius of a sphere is 1%. The error in the calculated value of its volume is

$\therefore V = \frac{4}{3}{\mathrm{\pi r}}^3$

$\therefore \% \mathrm{error} \mathrm{is} \mathrm{volume} = 3 \times \% \mathrm{error} \mathrm{in} \mathrm{radius}$

                                              $= 3\times 1 = 3\%$